2 moles of N_(2)H_(4) loses 16 moles of electrons is being converted to a new compound x. Assuming that all of the N appears in the new compound, what is the oxidation state of N in x?

2 moles of N_(2)H_(4) loses 16 moles of electrons is being converted t

1.	2 moles of N_(2)H_(4) loses 16 moles of electrons is being converted to a new compound x. Assuming that all of the N appears in the new compound, what is the oxidation state of N in x?
Answer» <html><body><p>`-1`<br/>`-2`<br/>`+2`<br/>`+<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`2N_(2)H_(4)rarrX+16e^(-)` <br/> `1N_(2)H_(4)rarr8e^(-)` <br/> i.e., n-factor = 8 = (`Delta` ox. No.) `xx2` <br/> implies `Delta` ox. No. = 4 <br/> Ox. No in `N_(2)H_(4)=-2` <br/> implies Final ox. No. `=-2+4=+2`</body></html>