2 moles of N_(2)O_(4) (g) is kept in a closed container at 298 K and 1 atm pressure. It is heated to 596 K when 20% by mass of N_(@)O_(4) (g) decomposes to NO_(2). The resulting pressure is

2 moles of N_(2)O_(4) (g) is kept in a closed container at 298 K and 1

1.	2 moles of N_(2)O_(4) (g) is kept in a closed container at 298 K and 1 atm pressure. It is heated to 596 K when 20% by mass of N_(@)O_(4) (g) decomposes to NO_(2). The resulting pressure is
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>2.<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> <a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a><br/>1.2 atm <br/>4.8 atm <br/>2.8 atm </p>Solution :Volume of the closed vessel (V)`=(<a href="https://interviewquestions.tuteehub.com/tag/nrt-1109890" style="font-weight:bold;" target="_blank" title="Click to know more about NRT">NRT</a>)/(P)` <br/> `=(2xx0.0821xx298)/(1)=48.9" L"` <br/> `N_(2)O_(4) <a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a> 2NO_(2)` <br/> `{:("Initial moles",2,0),("Moles after",2-(20)/(100)xx2,2xx0.4),("dissociation",=2-0.4,=0.8" mole"),(,=1.6"mole",):}` <br/> Tota moles present after heating`=1.6+0.8` <br/> `=2.4" moles"` <br/> `P=(nRT)/(V)=(2.4xx0.0821xx596)/(48.9)=2.4" atm"`</body></html>