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(2) Prove that a diagonal of a rhombus bisects twoopposite angles.FigureProof |
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Answer» Proof . – Let ABCD be a rhombus whose diagonal AC and BD intersect at the point O.We know that the diagonals of a parallelogram bisect each other.Also we know that every rhombus is a parallelogram.Therefore OA=OC and OB=OD.From triangle(COB) and triangle (COD), we have:CB=CD sides of rhombus.CO=CO. CommonOB=OD provedTherefore tri(COB)~tri(COD) by SSS congruence.=> But Thus, Hence, the diagonals of a rhombus bisect each other at right angles. |
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