20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample ? (At. Wt of Mg = 24)

20.0 g of a magnesium carbonate sample decomposes on heating to give c

1.	20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample ? (At. Wt of Mg = 24)
Answer» <html><body><p>96<br/><a href="https://interviewquestions.tuteehub.com/tag/84-339262" style="font-weight:bold;" target="_blank" title="Click to know more about 84">84</a><br/>60<br/>75</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(84g)(MgCO_(3))overset(<a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a>)(rarr)underset(40g)(MgO)+CO_(2)` <br/> 84 g of `MgCO_(3)` yield upon heating MgO = <a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> g <br/> 20 g of `MgCO_(3)` yield upon heating `MgO=((40g)xx(20g))/((84g))` <br/> `=9.52g` <br/> Weight of MgO <a href="https://interviewquestions.tuteehub.com/tag/actually-1968034" style="font-weight:bold;" target="_blank" title="Click to know more about ACTUALLY">ACTUALLY</a> formed = 8.0g <br/> % purity of `MgCO_(3)=((8.0g))/((9.52g))xx100=84%`.</body></html>