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20 ml of 0.1 M NH, solution is titrated with 0.025M HCI solution. What is the pH of the reaction mixture at equivalence point at 25^(@)C ? (K_(b) "of " NH_(3) "is " 2 xx 10^(-6)). |
Answer» <html><body><p><br/></p>Solution :` N_aV_a =N_b V_b ` <br/> ` 0.1 xx 20 = 0.025 xx V_b`` 0.1 xx 20 = 0.025 xx V_b rArr V_b = 80 ml` <br/>no . <a href="https://interviewquestions.tuteehub.com/tag/ofm-2202432" style="font-weight:bold;" target="_blank" title="Click to know more about OFM">OFM</a> moles of formed `NH_4Cl =<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`M _(NH_4Cl ) = ( <a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a> 10 ^(_3))/( 100 ) xx 1000 = 0.02M` <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/ph-1145128" style="font-weight:bold;" target="_blank" title="Click to know more about PH">PH</a> =7 - ((6- log 2)/(2)) -(1)/(2) ( Log 2- 2 ) rArr pH= 5`</body></html> | |