20 ml of 0.4 M H_(2),SO_(4) , and 80 ml of 0.2 M NaOH are mixed. Then the p^(H)of the resulting solution is

20 ml of 0.4 M H_(2),SO_(4) , and 80 ml of 0.2 M NaOH are mixed. Then

1.	20 ml of 0.4 M H_(2),SO_(4) , and 80 ml of 0.2 M NaOH are mixed. Then the p^(H)of the resulting solution is
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>`<br/>`1.097`<br/>`12.903`<br/>`11.903`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :` N_a = 0.4 xx 2 = 0. 8 M` <br/>` V_a = <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> ml ,N_b= 0.2 N, V_b = <a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a> ml ` <br/> ` N_aV_a = 0.8 xx 20 = 16 ` meq<br/> ` N_b V_b = 0.2 xx 8 0 = 16` meq <br/>` therefore N_aV_a = N_bV_b rArr pH = 7 ?`</body></html>