20 mL of HCl having a certain normality neutralises exactly 1.0 g CaCO_(3) . The normality of acid is

20 mL of HCl having a certain normality neutralises exactly 1.0 g CaCO

1.	20 mL of HCl having a certain normality neutralises exactly 1.0 g CaCO_(3) . The normality of acid is
Answer» <html><body><p>0.5 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a><br/>0.12 N<br/>0.01 N<br/>1.0 N</p>Solution :`underset((100 g))(CaCO_(3)) + underset((73 g))(2HCl) to CaCl_(2) + H_(2)O + CO_(2)` is<br/> 100 g of `CaCO_(3)` shall be <a href="https://interviewquestions.tuteehub.com/tag/neutralised-2188316" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRALISED">NEUTRALISED</a> by<br/> `(73)/(100)=0.73 g ` HCl <br/> `therefore 20` mL of HCl has HCl in equivalent `=(0.73)/(36.5)` <br/> Hence Normality `=(0.73)/(36.5)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(1000)/(20)=1.0 N`</body></html>