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20 % of N_(2)O_(4) " molecules are disociated in a sample of a gas at " 27^(@)C and 760 " torr . Calculate the density of the equilibrium mixture ".

Answer» <html><body><p></p>Solution :` {:(,N_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)(g),hArr,2NO_(2)(g),),("Intial",1 " mole",,,),("At.eqm.",1-0*2 = 0*<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>" mole",,0*4 "mole,",Total = 1*2 " moles" ):}` <br/> If V is the volume of the vapour <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> mole, volume of vapour before dissociation = V<br/> ` " Hence density " (D) propto1/V ` <br/> But density after dissociation <br/>`D= (" Mol.wt.of " N_(2)O_(4))/2 = 92/2=46"" ("Theoretical density")` <br/> Volume after dissociation = `1*2` V<br/>` :. "Density (d)" propto 1/(1*2 V) `<br/>` :.D/d = 1/V xx 1*2V =1*<a href="https://interviewquestions.tuteehub.com/tag/2or-1838480" style="font-weight:bold;" target="_blank" title="Click to know more about 2OR">2OR</a> d=D/(1*2)= 46/(1*2)= 38*3` <br/> Alternatively, <a href="https://interviewquestions.tuteehub.com/tag/use-1441041" style="font-weight:bold;" target="_blank" title="Click to know more about USE">USE</a> theformula directly, <br/> ` alpha = (D-d)/d`</body></html>


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