1.

20 volume H_2O_2 Solution has a strength of about

Answer» <html><body><p>`30%`<br/>`6%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>%`<br/>`10%`</p>Solution :22.4 <a href="https://interviewquestions.tuteehub.com/tag/litre-1075864" style="font-weight:bold;" target="_blank" title="Click to know more about LITRE">LITRE</a> `O_2` at N.T.P. <a href="https://interviewquestions.tuteehub.com/tag/obtained-7273275" style="font-weight:bold;" target="_blank" title="Click to know more about OBTAINED">OBTAINED</a> by 68 gm of `H_2O_2` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> litre `O_2` at N.T.P. obtained by `68/22.4` gm of `H_2O_2`<br/> `therefore` 20 litre `O_2` at N.T.P. obtained by `68/22.4xx20` gm of `H_2O_2` =60.71 gm of `H_2O_2` <br/> `therefore` 1000 ml `O_2` at N.T.P. obtained by =60.71 gm of `H_2O_2` <br/> `therefore` 100 ml `O_2` at N.T.P. obtained by `=60/1000xx100`=6.71%</body></html>


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