200 g of ice at −20∘C is mixed with 500 g of water at 20∘C in an insulating vessel. Final mass of the water in the vessel is -(specific heat of ice =0.5 cal g−1∘C−1 & specific heat of water =1 cal g−1∘C−1)

200 g of ice at −20∘C is mixed with 500 g of water at 20∘C in an

1.	200 g of ice at −20∘C is mixed with 500 g of water at 20∘C in an insulating vessel. Final mass of the water in the vessel is -(specific heat of ice =0.5 cal g−1∘C−1 & specific heat of water =1 cal g−1∘C−1)
Answer» $200 g$ of ice at $- 20^{\circ} C$ is mixed with $500 g$ of water at $20^{\circ} C$ in an insulating vessel. Final mass of the water in the vessel is - (specific heat of ice $= 0.5 {cal g}^{- 1} {^{\circ} C}^{- 1}$ & specific heat of water $= 1 {cal g}^{- 1} {^{\circ} C}^{- 1}$ )

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200 g of ice at −20∘C is mixed with 500 g of water at 20∘C in an insulating vessel. Final mass of the water in the vessel is -(specific heat of ice =0.5 cal g−1∘C−1 & specific heat of water =1 cal g−1∘C−1)

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