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20CC of hydro carbon were exploded with excess of oxygen. After explosion and cooling a contraction of 20cc was noted on addition of KOH another contraction of 40CC was noted. The molecular formula of hydrocarbon is

Answer» <html><body><p>`C_(2)H_(6)`<br/>`C_(2)H_(4)`<br/>`C_(2)H_(2)` <br/>`CH_(4)`</p>Solution :Let formula of hydrocarbon = <a href="https://interviewquestions.tuteehub.com/tag/cxhy-428877" style="font-weight:bold;" target="_blank" title="Click to know more about CXHY">CXHY</a> <br/> `CxHY+(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>+(y)/(4))O_(2)rarrxCO_(2)+(y)/(2)H_(2)O` <br/> `{:("1 mol",(x+(y)/(4))"mol","x mol"),("1 vol",(x+y//4)"vol","x vol"),(20C <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>,20(x+(y)/(4))C C,20xC C):}` <br/> `CO_(2)` <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a> = contraction on addition of KOH <br/> = 40 CC implies 20x = 40 implies x = 2 <br/> `[20C C+20(x+(y)/(4))C C]-20xC C=30C C` <br/> `y=2` <br/> Formula of hydrocarbon =`C_(2)H_(2)`</body></html>


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