225 ml of 0.1 M acetic acid is titrated with 0.1 MNaOH solution. The p – InterviewSolution

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1.	225 ml of 0.1 M acetic acid is titrated with 0.1 MNaOH solution. The pH of the solution atequivalence point will be (log 5 = 0.7 and pKa ofCH,COOH 4.76)(1) 8.73(2) 9.73(4) 8.212(3) 7.13
Answer» 225 ml of 0.1 M acetic acid is titrated with 0.1 MNaOH solution. The pH of the solution atequivalence point will be (log 5 = 0.7 and pKa ofCH,COOH 4.76)(1) 8.73(2) 9.73(4) 8.212(3) 7.13

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