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24 g of magnesium in the vapour state absorb 1200 kJ of energy. If IE_1 and IE_2 of magnesium are 750 and 1450 kJ mol^(-1) respectively, the final composition of mixture is

Answer» <html><body><p>0.69 <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> `<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>^(+)` and 0.31 mol `Mg^(2+)`<br/>0.59 mol `Mg^(+)` and 0.41 mol `Mg^(2+)`<br/>0.49 mol `Mg^(+)` and 0.51 mol `Mg^(2+)`<br/>0.29 mol `Mg^(+)` and 0.71 mol `Mg^(2+)`<br/></p>Solution :Molar <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of Mg =24 g `mol^(-1)` <br/> `:.` Amount of Mg=1 mol <br/> <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, 750 kJ of energy is used up to convert 1 mol of Mg to `Mg^(+)`<br/> Energy used to convert `Mg^(+)` to `Mg^(2+)` <br/> `=1200-750 =<a href="https://interviewquestions.tuteehub.com/tag/450-317308" style="font-weight:bold;" target="_blank" title="Click to know more about 450">450</a> kJ` <br/> `:.` Amount of magnesium converted to `Mg^(2+)` <br/> `=(450 kJ)/(1450) =0.31 mol` <br/> `:. ` Amount of magnesium converted to `Mg^(+)` <br/> =1-0.31 =0.69 mol</body></html>


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