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24 ml of water gas containing only hydrogen and carbon monoxide in equal proportions by volume are exploded with 80 ml of air in which 20% by volumeis O_2 , if all gasesous are measured at room temperature and pressure , calculate the composition by volume of the unreacted resulting gaseous mixture .

Answer» <html><body><p>`O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) to 12 mlN_(2) to 64 ml CO_(2) to4 ml`<br/>`O_(2) to 4 ml N_(2) to 12 ml CO_(2) to 64 ml`<br/>`O_(2) to 64 ml N_(2) to 4 ml CO_(2) to 12 ml`<br/>`O_(2) to 4 mlN_(2) to64 ml CO_(2) to 12 ml`</p>Solution :`underset("2 volume") underset(12) (2 H_(2)) + underset("1 volume") underset(6) (O_(2)) to underset("zero volume") (2 H_(2) O) `(liq) <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) `underset(" 2 volume") underset(12) (2 CO) + underset(" 1 volume") underset(6) (O_(2)) to underset(2 " volume") (2 CO_(2)) (12 ml)`<br/> Total <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a> <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> 6 +6= 12 ml <br/> Total oxygen <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> in 80 ml of air = `80 xx 20//100 = 16 ` ml <br/> Un used = 4 ml <br/> `N_(2) = 64` ml <br/> `CO_(2) = 12` ml</body></html>


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