24 ml of water gas containing only hydrogen and carbon monoxide in equal proportions by volume are exploded with 80 ml of air in which 20% by volumeis O_2 , if all gasesous are measured at room temperature and pressure , calculate the composition by volume of the unreacted resulting gaseous mixture .

24 ml of water gas containing only hydrogen and carbon monoxide in equ

1.	24 ml of water gas containing only hydrogen and carbon monoxide in equal proportions by volume are exploded with 80 ml of air in which 20% by volumeis O_2 , if all gasesous are measured at room temperature and pressure , calculate the composition by volume of the unreacted resulting gaseous mixture .
Answer» `O_(2) to 12 mlN_(2) to 64 ml CO_(2) to4 ml` `O_(2) to 4 ml N_(2) to 12 ml CO_(2) to 64 ml` `O_(2) to 64 ml N_(2) to 4 ml CO_(2) to 12 ml` `O_(2) to 4 mlN_(2) to64 ml CO_(2) to 12 ml` Solution :`underset("2 volume") underset(12) (2 H_(2)) + underset("1 volume") underset(6) (O_(2)) to underset("zero volume") (2 H_(2) O) `(liq) (II) `underset(" 2 volume") underset(12) (2 CO) + underset(" 1 volume") underset(6) (O_(2)) to underset(2 " volume") (2 CO_(2)) (12 ml)` Total OXYGEN USED 6 +6= 12 ml Total oxygen PRESENT in 80 ml of air = `80 xx 20//100 = 16 ` ml Un used = 4 ml `N_(2) = 64` ml `CO_(2) = 12` ml