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25.0 g of FeSO_(4).7H_(2)O was dissolved in water containing dilute H_(2)SO_(4) and the volume was made up to 1.0 L. 25.0 " mL of " this solution requried 20 " mL of " an (N)/(10) KMnO_(4) solution for complete oxidation the percentage of FeSO_(4)7H_(2)O in the acid solution is |
Answer» <html><body><p>`78%`<br/>`98%`<br/>`89%`<br/>`79%`</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/V_PHY_CHM_P1_C03_E01_246_S01.png" width="80%"/> <br/> `implies((W_(FeSO_(4).7H_(2)O)xx1000)/((278)/(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))=80` <br/> `impliesW_(FeSO_(4).7H_(2)O)=22.24` <br/> `implies% of FeSO_(4).6H_(2)O=(22.24)/(25)<a href="https://interviewquestions.tuteehub.com/tag/xx100-3292680" style="font-weight:bold;" target="_blank" title="Click to know more about XX100">XX100</a>%=88.96%`</body></html> | |