25 kg of N2 and 6 kg of H2 are mixed to produce NH3.(i) Identify the l

1.	25 kg of N2 and 6 kg of H2 are mixed to produce NH3.(i) Identify the limiting reagent.(ii) Calculate the amount of ammonia formed in this reaction.
Answer» N₂ + 3H₂→ 2NH₃ (i) 1 mole N₂ requires 3 moles of H₂ \(\because\)28 kg N₂ require 6 kg H₂ \(\therefore\)25 kg N₂will require = \(\frac{6}{28}\) x 25 = 5.36 kg H₂ Hence, N₂ is the limiting reagent. (ii) 1 N₂ produces 2 moles NH₃ \(\because\) 28 kg N₂ produce 34 moles NH₃ \(\therefore\) 25 kg N₂ will produce = \(\frac{34}{28}\) x 25 = 30.26 kg NH₃

25 kg of N2 and 6 kg of H2 are mixed to produce NH3.(i) Identify the limiting reagent.(ii) Calculate the amount of ammonia formed in this reaction.

Answer»

N₂ + 3H₂→ 2NH₃

(i) 1 mole N₂ requires 3 moles of H₂

\(\because\)28 kg N₂ require 6 kg H₂

\(\therefore\)25 kg N₂will require = \(\frac{6}{28}\) x 25 = 5.36 kg H₂

Hence, N₂ is the limiting reagent.

(ii) 1 N₂ produces 2 moles NH₃

\(\because\) 28 kg N₂ produce 34 moles NH₃

\(\therefore\) 25 kg N₂ will produce = \(\frac{34}{28}\) x 25

= 30.26 kg NH₃