25 mL 0.1 N H_(2)SO_(4) neutralized with 20 mL xN Na_(2)CO_(3).What will be the g/liter of Na_(2)CO_(3) ?

25 mL 0.1 N H_(2)SO_(4) neutralized with 20 mL xN Na_(2)CO_(3).What wi

1.	25 mL 0.1 N H_(2)SO_(4) neutralized with 20 mL xN Na_(2)CO_(3).What will be the g/liter of Na_(2)CO_(3) ?
Answer» <html><body><p>8.48 g<br/>4.24 g<br/><a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>.625 g<br/>13.<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> g </p>Solution :`N_(1)V_(1) =N_(2)V_(2)` <br/> `(0.1)(25) =(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)(<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)` <br/> `:.x=(0.1xx25)/(20)` <br/> `:.N_(2)=0.125` <br/> `:.0.125 N Na_(2)CO_(3) = (0.125)/(2)` <br/> `= 0.0625 M Na_(2)CO_(3)` solution <br/> `= 0.0625xx10^(6) g//L` <br/> `=6.625 g`</body></html>