25 mL 0.1 N H_(2)SO_(4) neutralized with 20 mL xN Na_(2)CO_(3).What will be the g/liter of Na_(2)CO_(3) ?

25 mL 0.1 N H_(2)SO_(4) neutralized with 20 mL xN Na_(2)CO_(3).What wi

1.	25 mL 0.1 N H_(2)SO_(4) neutralized with 20 mL xN Na_(2)CO_(3).What will be the g/liter of Na_(2)CO_(3) ?
Answer» 8.48 g 4.24 g 6.625 g 13.25 g Solution :`N_(1)V_(1) =N_(2)V_(2)` `(0.1)(25) =(X)(20)` `:.x=(0.1xx25)/(20)` `:.N_(2)=0.125` `:.0.125 N Na_(2)CO_(3) = (0.125)/(2)` `= 0.0625 M Na_(2)CO_(3)` solution `= 0.0625xx10^(6) g//L` `=6.625 g`