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25 mL of a solution of barium hydroxide on titration with a 0.1 molar solution of hydrochloric acid gave a titre value of 35 mL. The molarity of barium hydroxide solution was : |
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Answer» 0.28 No. of moles of `HCl=(("0.1 mol"^(-1)))/(("1L"))xx("0.035L")` `=3.5xx10^(-3)` mol No. of moles of `Ba(OH)_(2)=(3.5xx10^(-3))/(2)` `=1.75xx10^(-3)` mol MOLARITY of `Ba(OH)_(2)` solution `= ("No. of moles of Ba"("OH")_(2))/("Volume of solution in litres")` `=((1.75xx10^(-3)"mol"))/(("0.025 L"))=0.07"mol L"^(-1)` `=0.07M`. |
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