25 mL of N/10 NaOHsolution exactly neutralise 20 mL of an acid solution. What is the normality of the acid solution ?

25 mL of N/10 NaOHsolution exactly neutralise 20 mL of an acid solutio

1.	25 mL of N/10 NaOHsolution exactly neutralise 20 mL of an acid solution. What is the normality of the acid solution ?
Answer» Solution :According to the normality relation, `underset("NaOH")(N_(1)V_(1)) = underset("acid")(N_(2)V_(2))` In the present CASE, `N_(1) = 1/10, V_(1) = 25 ML, N_(2) = ?,V_(2) = 20 mL` SUBSTITUTING the values, we have `1/10 xx 25 = N_(2) xx 20` `therefore N_(2) = 25/(10 xx 20)= 0.125` Hence, the normality of the acid solution is 0.125 N