25 mL of N/10 NaOHsolution exactly neutralise 20 mL of an acid solution. What is the normality of the acid solution ?

25 mL of N/10 NaOHsolution exactly neutralise 20 mL of an acid solutio

1.	25 mL of N/10 NaOHsolution exactly neutralise 20 mL of an acid solution. What is the normality of the acid solution ?
Answer» <html><body><p></p>Solution :According to the normality relation, <br/> `underset("NaOH")(N_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)V_(1)) = underset("acid")(N_(2)V_(2))` <br/> In the present <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a>, `N_(1) = 1/10, V_(1) = 25 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>, N_(2) = ?,V_(2) = <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> mL` <br/> <a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> the values, we have `1/10 xx 25 = N_(2) xx 20` <br/> `therefore N_(2) = 25/(10 xx 20)= 0.125` <br/> Hence, the normality of the acid solution is 0.125 N</body></html>