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25mLof decimolar solution of a stable divalent transition metal cation is oxidised by 50mL of 0.02M acidified permanganate solution. What is the final oxidation state of the metal? |
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Answer» Solution :5 moles of `M^(2+)` ion =x moles of permanganate , where x is the increase in oxidation number of the metal ion, `M^(2+)` Using the MOLARITY EQUATION for the TITRATION `(V_(1)M_(1))/(5)=(V_(2)M_(2))/(x)` The final oxidation state of metal `=+2-(-2)=+4` |
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