1.

25mLof decimolar solution of a stable divalent transition metal cation is oxidised by 50mL of 0.02M acidified permanganate solution. What is the final oxidation state of the metal?

Answer»

Solution :5 moles of `M^(2+)` ion =x moles of permanganate , where x is the increase in oxidation number of the metal ion, `M^(2+)`
Using the MOLARITY EQUATION for the TITRATION
`(V_(1)M_(1))/(5)=(V_(2)M_(2))/(x)`
The final oxidation state of metal `=+2-(-2)=+4`


Discussion

No Comment Found