29.5 mg of an organic compound containing nitrogen was digested according to Kjeldahl's method and the evolved ammonia was absorbed in 20 mL of 0.1 M HCl solution. The exess of the acid required 15 mL of 0.1 M NaOH solution for complete neutralization. The percentage of nitrogen in the compound is

29.5 mg of an organic compound containing nitrogen was digested accord

1.	29.5 mg of an organic compound containing nitrogen was digested according to Kjeldahl's method and the evolved ammonia was absorbed in 20 mL of 0.1 M HCl solution. The exess of the acid required 15 mL of 0.1 M NaOH solution for complete neutralization. The percentage of nitrogen in the compound is
Answer» <html><body><p>29.5<br/>`59.0`<br/>47.4<br/>23.7</p>Solution :Weight of substance <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> `= 29.5 xx 10^(-3) g` <br/> Volume of <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> taken <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> mL of 0.1 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> HCl <br/> `:.` Volume of acid used = 20 - <a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> = 5 mL of 0.1 N HCl <br/> `%N= (1.4 xx "Volume" xx "Normality")/("Weight of substance taken") = (1.4 xx 5 xx 0.1)/(29.5 xx 10^(-3))`<br/> `= 23.73`</body></html>