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2CaSO_(4)(s)hArr22CaO(s)+2SO_(2)(g)+O_(2)(g), DeltaHgt0 Above equilibrium is established by taking some amout of CaSO_(4)(s) in a closed container at 1600K Then which of the following may be correct option.

Answer» <html><body><p>Moles of `<a href="https://interviewquestions.tuteehub.com/tag/cao-411869" style="font-weight:bold;" target="_blank" title="Click to know more about CAO">CAO</a>(s)` will increase with the increase in temperature<br/>If the voulme of the container is doubled at equilibrium then partial pressure of `SO_(2)(g)` will <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> at new equilibrium<br/>If the volume of the container is halved partial pressure of `O_(2)(g)` at new equilibrium will remain same <br/>If two moles of the He gas is added at constant pressure then the moles of `CaO(s)` will increase.</p>Solution :(A) As reaction is endothermic therefore it will <a href="https://interviewquestions.tuteehub.com/tag/go-468886" style="font-weight:bold;" target="_blank" title="Click to know more about GO">GO</a> in the forward direction hence moles of `CaO` will increase. <br/> (B) With the increase or decrease of volume partial pressure of the gases will remain same. <br/> (C) Due to the <a href="https://interviewquestions.tuteehub.com/tag/addition-367641" style="font-weight:bold;" target="_blank" title="Click to know more about ADDITION">ADDITION</a> of inert gas at constant pressure reaction will proceed in the direction in which more number of <a href="https://interviewquestions.tuteehub.com/tag/gaseous-467815" style="font-weight:bold;" target="_blank" title="Click to know more about GASEOUS">GASEOUS</a> moles are formed.</body></html>


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