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2d) law of conHow many moles are present in 11.5 g of sodium ?(a) 0.5 mol(b) 5.0 mol(c) 0.05 mol(d) 1.5 molof the following the valency of each of the |
| Answer» <html><body><p><strong>Answer:</strong></p><p>(a) 0.5 molecular</p><p><strong>Explanation:</strong></p><p>The <a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> mass of <a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a> is equal to 23g/mol.</p><p>The formula to find out the number of moles is given by \frac{weight}{molar mass}. </p><p>molarmass</p><p>weight</p><p> </p><p> . .</p><p><a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> the number of moles in 11.5g of sodium or Na is equal to \frac{11.5}{23} </p><p>23</p><p>11.5</p><p> </p><p> which gives us 0.5.</p><p>Now to further find out the value of the amount of the atoms present in it then we multiply the <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> number of given moles in it to the Avogadro number which is $$6.022\times 10^2^3$$ therefore $$0.3\times6.022\times10^2^3$$ is $$3.011\times10^2^3.$$ .</p></body></html> | |