2g of Al is treated separately with excess dilute H_2SO_4 andexcess NaOH.The ratio of volumes of Hydrogen evolved under similar condition is x y. Find x/y

2g of Al is treated separately with excess dilute H_2SO_4 andexcess Na

1.	2g of Al is treated separately with excess dilute H_2SO_4 andexcess NaOH.The ratio of volumes of Hydrogen evolved under similar condition is x y. Find x/y
Answer» SOLUTION :`2Al+3H_(2)SO_(4) to Al_(2)(SO_(4))_(3)+3H_(2)` `2Al+2NaOH+2H_(2) 2NaAlO_(2)+3H_(2)` Ratio is 1:1