2H_(2)O(g) hArr 2H_(2)(g) + O_(2)(g) K_(C) = 4.1 xx 10^(-48) At 599 K N_(2)(g) +O_(2)(g) hArr hArr 2NO(g) K_(c)= 1 xx 10^(-30) at 1000 K Predict the extent of the above two reactions.

2H_(2)O(g) hArr 2H_(2)(g) + O_(2)(g) K_(C) = 4.1 xx 10^(-48) At 599 K

1.	2H_(2)O(g) hArr 2H_(2)(g) + O_(2)(g) K_(C) = 4.1 xx 10^(-48) At 599 K N_(2)(g) +O_(2)(g) hArr hArr 2NO(g) K_(c)= 1 xx 10^(-30) at 1000 K Predict the extent of the above two reactions.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In the reactions , decomposition of water at 500 K and oxidation of <a href="https://interviewquestions.tuteehub.com/tag/nitrogen-1118291" style="font-weight:bold;" target="_blank" title="Click to know more about NITROGEN">NITROGEN</a> at <a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a> K, the value, of `K_(c)` is very less `K_(c) lt 10^(-3)` . So reverse reaction is <a href="https://interviewquestions.tuteehub.com/tag/favoured-7681397" style="font-weight:bold;" target="_blank" title="Click to know more about FAVOURED">FAVOURED</a> <br/> `therefore` Products << <a href="https://interviewquestions.tuteehub.com/tag/reactants-1178112" style="font-weight:bold;" target="_blank" title="Click to know more about REACTANTS">REACTANTS</a></body></html>