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2Mn_(2)O_7rarr4MnO_(2)+ 3O_2(If M is mol. wt. of Mn_(2)O_7). Find the equivalent, weight of Mn_2O_7in the above change. |
Answer» <html><body><p><br/></p>Solution :`Mn_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)^(7+) +<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> e rarr 2Mn^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>+)` <br/> 2 `xx` <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> of `Mn_(2) O_(7) =4xx` mole of `MnO_2` <br/> `=4xx3 xx` eq. of `MnO_2 =<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> ` eq. of `MnO_2` <br/> `:.` Mole of `Mn_(2)O_(7) = 6 ` eq. of `MnO_2` <br/> `:. ` Eq. of `Mn_(2) O_(7) ` = Eq. of `MnO_7` <br/> `:.` Eq. wt. of `Mn_(2) O_(7) = M//6`</body></html> | |