1.

2Mn_(2)O_7rarr4MnO_(2)+ 3O_2(If M is mol. wt. of Mn_(2)O_7). Find the equivalent, weight of Mn_2O_7in the above change.

Answer»


Solution :`Mn_(2)^(7+) +6 e rarr 2Mn^(4+)`
2 `xx` MOLE of `Mn_(2) O_(7) =4xx` mole of `MnO_2`
`=4xx3 xx` eq. of `MnO_2 =12 ` eq. of `MnO_2`
`:.` Mole of `Mn_(2)O_(7) = 6 ` eq. of `MnO_2`
`:. ` Eq. of `Mn_(2) O_(7) ` = Eq. of `MnO_7`
`:.` Eq. wt. of `Mn_(2) O_(7) = M//6`


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