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2Mn_(2)O_7rarr4MnO_(2)+ 3O_2(If M is mol. wt. of Mn_(2)O_7). Find the equivalent, weight of Mn_2O_7in the above change. |
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Answer» 2 `xx` MOLE of `Mn_(2) O_(7) =4xx` mole of `MnO_2` `=4xx3 xx` eq. of `MnO_2 =12 ` eq. of `MnO_2` `:.` Mole of `Mn_(2)O_(7) = 6 ` eq. of `MnO_2` `:. ` Eq. of `Mn_(2) O_(7) ` = Eq. of `MnO_7` `:.` Eq. wt. of `Mn_(2) O_(7) = M//6` |
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