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2Na_(2)S_(2)O_(3)+I_(2)toNa_(2)S_(4)O_(6)+2NaI How many equivalents ofHypo is oxidised by one mole of Iodine? |
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Answer» EQ wt of `Na_(2)S_(2)O_(3)=("MOL wt of"Na_(2)S_(2)O_(3))/(1)` EQ wt of Iodine = `("Mol wt of iodine")/(2)` 1 mole iodine = 2 equivalents iodine = 2 equivalents hypo |
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