1.

2Na_(2)S_(2)O_(3)+I_(2)toNa_(2)S_(4)O_(6)+2NaI How many equivalents ofHypo is oxidised by one mole of Iodine?

Answer»


SOLUTION :`2Na_(2)overset(+2)(S_(2))O_(3)+overset(0)I_(2)rarrNa_(2)overset(+2.5)(S_(4))O_(6)+2NaI^(-1)`
EQ wt of `Na_(2)S_(2)O_(3)=("MOL wt of"Na_(2)S_(2)O_(3))/(1)`
EQ wt of Iodine = `("Mol wt of iodine")/(2)`
1 mole iodine = 2 equivalents iodine
= 2 equivalents hypo


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