1.

`{:(2NaOH+H_(2)SO_(4)rarrNa_(2)SO_(4)+2H_(2)O),("Base Acid"):}`

Answer» Valency factor of base = 1
Here, two molecule of NaOH replaced `2H^(+)` ion from the `H_(2) SO_(4)`. Therefore, each molecule of NaOH replaced only one `H^(+)` ion of acid, so v.f = 1.


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