2O_3 harr 3O_2 Ozone dissociates until the molecular weight of the equilibrium mixture becomes 40. Initial pressure of O_3 is 600 mm Hg. Then

2O_3 harr 3O_2 Ozone dissociates until the molecular weight of the equ

1.	2O_3 harr 3O_2 Ozone dissociates until the molecular weight of the equilibrium mixture becomes 40. Initial pressure of O_3 is 600 mm Hg. Then
Answer» <html><body><p>`K_p = 360` mm<br/>degree of <a href="https://interviewquestions.tuteehub.com/tag/dissociation-15685" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOCIATION">DISSOCIATION</a> = 0.4<br/>`P_(eq) = <a href="https://interviewquestions.tuteehub.com/tag/720-334419" style="font-weight:bold;" target="_blank" title="Click to know more about 720">720</a>` mm <br/>`K_p = p_(O)_3 = P_(O)_2`</p>Solution :`(D)/(d)=1+(n-1)alpha, (48)/(40)=1+((3)/(2)-1)alpha, alpha=40%` <br/> `2O_(3) harr 3O_(2)` <br/> at <a href="https://interviewquestions.tuteehub.com/tag/eqm-446398" style="font-weight:bold;" target="_blank" title="Click to know more about EQM">EQM</a> `<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(=360)(600(1-alpha))""underset(360)((3alpha)/(2) xx 600)` <br/> `K_(P)=((360)^(3))/((360)^(2))=360`</body></html>