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3.15 g of oxalic acid dihydrate is dissolved in water and the solution was made up to 100 ml using a standard flask. The strength of the solution in normality is …………… |
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Answer» Solution :`0.5N` Normality `= ("Number of gram equivalents")/("Volume of the solution in L")` `= ("Mass of oxalic ACID")/(" EQUIVALENT mass of oxalic acid") + ` Volume of the solution in L `= ((3.15)/(63))/(0.1) = (0.05)/(0.1) =0.5N` |
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