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3.15 g of oxalic acid dihydrate is dissolved in water and the solution was made up to 100 ml using a standard flask. The strength of the solution in normality is ……………

Answer» <html><body><p></p>Solution :`0.5N` <br/> Normality `= ("Number of gram equivalents")/("Volume of the solution in L")` <br/> `= ("Mass of oxalic <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>")/(" <a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> mass of oxalic acid") + ` Volume of the solution in L <br/> `= ((3.15)/(63))/(0.1) = (0.05)/(0.1) =0.5N`</body></html>


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