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3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are |
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Answer» `3.67xx10^(26)` `=(6.02xx10^(23)xx11xx34.2)/(342) = 6.62xx10^(23)` Number of oxygen atoms in 9 g of `H_2O` `=(6.02xx10^(23)xx90)/(18) =30.1xx10^(23)` Total number of oxygen atoms `(30.1 +6.62)10^(23)` `=36.72xx10^(23) = 3.672xx10^(24)` |
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