3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are

3.42 g of sucrose are dissolved in 18g of water in a beaker. The numbe

1.	3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are
Answer» <html><body><p>`3.67xx10^(26)`<br/>`6.6 xx 10^(23)`<br/>`3.67xx10^(<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>)`<br/>`6.0 xx10^(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)`</p>Solution :Number of <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a> atoms in 34.2 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> of sucrose <br/> `=(6.02xx10^(23)xx11xx34.2)/(342) = 6.62xx10^(23)` <br/> Number of oxygen atoms in 9 g of `H_2O` <br/> `=(6.02xx10^(23)xx90)/(<a href="https://interviewquestions.tuteehub.com/tag/18-278913" style="font-weight:bold;" target="_blank" title="Click to know more about 18">18</a>) =30.1xx10^(23)` <br/> Total number of oxygen atoms `(30.1 +6.62)10^(23)` <br/> `=36.72xx10^(23) = 3.672xx10^(24)`</body></html>