1.

3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are

Answer»

`3.67xx10^(26)`
`6.6 xx 10^(23)`
`3.67xx10^(24)`
`6.0 xx10^(22)`

Solution :Number of OXYGEN atoms in 34.2 G of sucrose
`=(6.02xx10^(23)xx11xx34.2)/(342) = 6.62xx10^(23)`
Number of oxygen atoms in 9 g of `H_2O`
`=(6.02xx10^(23)xx90)/(18) =30.1xx10^(23)`
Total number of oxygen atoms `(30.1 +6.62)10^(23)`
`=36.72xx10^(23) = 3.672xx10^(24)`


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