3.45 g of a metallic carbonate were mixed with 240 mL of N//4 HCl. The excess acid was neutralised by 50 mL of N//5 KOH solution. Calculate the equivalent mass of the metal.

3.45 g of a metallic carbonate were mixed with 240 mL of N//4 HCl. The

1.	3.45 g of a metallic carbonate were mixed with 240 mL of N//4 HCl. The excess acid was neutralised by 50 mL of N//5 KOH solution. Calculate the equivalent mass of the metal.
Answer» SOLUTION :Equivalent MASS of metal carbonate `=(3.45xx4xx1000)/(200)=69` Equivalent mass of metal =69- EQ. mass of carbonate =(69-30)=39