3.45 g of a metallic carbonate were mixed with 240 mL of N//4 HCl. The excess acid was neutralised by 50 mL of N//5 KOH solution. Calculate the equivalent mass of the metal.

3.45 g of a metallic carbonate were mixed with 240 mL of N//4 HCl. The

1.	3.45 g of a metallic carbonate were mixed with 240 mL of N//4 HCl. The excess acid was neutralised by 50 mL of N//5 KOH solution. Calculate the equivalent mass of the metal.
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Equivalent <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of metal carbonate <br/> `=(3.45xx4xx1000)/(<a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a>)=69` <br/> Equivalent mass of metal =69- <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. mass of carbonate <br/> =(69-30)=39</body></html>