3 g of activated chasrcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is :

3 g of activated chasrcoal was added to 50 mL of acetic acid solution

1.	3 g of activated chasrcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is :
Answer» 18 mg 36 mg 42 mg 54 mg SOLUTION :Number of moles of acetic acid adsorbed `= (0.06xx(50)/(1000)-0.042xx(50)/(1000))` `= (0.9)/(1000)` moles. `THEREFORE` Weight of acetic acid adsorbed `= 0.9xx60 mg` = 54 mg Hence, the amount of acetic acid adsorbed per g of charcoal `= (54)/(3)` mg = 18 mg Hence, option (A) is correct.