1.

3 g of an oxide of a metal Is converted to chloride completely and it yielded 5 g of chloride. The equivalent weight of the matel is

Answer»

33.25
3.325
12
20

Solution :a) `("Weight of METAL OXIDE")/("Weight of metal chloride")`
`= `("Eq.WT. of metal" + "Eq.wt. of oxide")/("Eq.wt. of metal"+"Eq. wt. of chloride")`
`3/5`=`(E+8)/(E+35.5)`
Or 5E = 40 = 3E + 106.5 or 2E = 66.5
`therefore` E=33.25


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