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3 moles of a gas are present in a vessel at a temperature of 27^@C. What will be the value of R, the gas constant, in terms of the kinetic energy of the molecules of the gas ? |
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Answer» `K.E. = n 3/2 RT` `:. " The kinetic energy of 3 moles of a gas at " 27^@C (300 K)` will be given by `K.E. = 3xx 3/2 XX R xx 300` `:. "" R =(2 xx K.E.)/(3xx3xx300)= 7.41 xx 10&(-4) xx K.E`. HENCE, the value of R is `7.41 xx 10^(-4) " K.E. " K^(-1)` |
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