3 moles of a mixture of FeSO_(4) and Fe_(2)(SO_(4))_(3) required 100 mL of 2 M KMnO_(4) solution in acidic medium. Hence, mole fraction of FeSO_(4) in the mixture is

3 moles of a mixture of FeSO_(4) and Fe_(2)(SO_(4))_(3) required 100 m

1.	3 moles of a mixture of FeSO_(4) and Fe_(2)(SO_(4))_(3) required 100 mL of 2 M KMnO_(4) solution in acidic medium. Hence, mole fraction of FeSO_(4) in the mixture is
Answer» <html><body><p>`(1)/(3)`<br/>`(2)/(3)`<br/>`(2)/(5)`<br/>`(3)/(5)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> moles of `FeSO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)=x` <br/> <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. `FeSO_(4)` = eq. `KMnO_(4)` <br/> `x xx1=0.1xx2xx5impliesx=1` <br/> `therefore` mole <a href="https://interviewquestions.tuteehub.com/tag/fraction-458259" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTION">FRACTION</a> =1/3</body></html>