3 moles of a mixture of FeSO_(4) and Fe_(2)(SO_(4))_(3) required 100 mL of 2 M KMnO_(4) solution in acidic medium. Hence, mole fraction of FeSO_(4) in the mixture is

3 moles of a mixture of FeSO_(4) and Fe_(2)(SO_(4))_(3) required 100 m

1.	3 moles of a mixture of FeSO_(4) and Fe_(2)(SO_(4))_(3) required 100 mL of 2 M KMnO_(4) solution in acidic medium. Hence, mole fraction of FeSO_(4) in the mixture is
Answer» `(1)/(3)` `(2)/(3)` `(2)/(5)` `(3)/(5)` Solution :LET moles of `FeSO_(4)=x` EQ. `FeSO_(4)` = eq. `KMnO_(4)` `x xx1=0.1xx2xx5impliesx=1` `therefore` mole FRACTION =1/3