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30.4 kJ is required to melt one mole of sodium chloride. The entropy change during melting is 28.4 JK^(-1)mol^(-1) . Calculate the melting point of sodium chloride. |
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> : `DeltaH_f (NaCl)=30.4 kJ =30400 "<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a> <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>"^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> `DeltaS_f (NaCl)=28.4 <a href="https://interviewquestions.tuteehub.com/tag/jk-521675" style="font-weight:bold;" target="_blank" title="Click to know more about JK">JK</a>^(-1) mol^(-1)` <br/> `T_f`=? <br/>`DeltaS_f =(DeltaH_f)/(DeltaT_f)` <br/> `T_f =(DeltaH_f)/(DeltaS_f)` <br/> `T_f=(30400 "J mol"^(-1))/(28.4 J K^(-1) "mol"^(-1))` <br/> `T_f` =1070.4 K</body></html> | |