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30.4 kJ is required to melt one mole of sodium chloride. The entropy change during melting is 28.4 JK^(-1)mol^(-1) . Calculate the melting point of sodium chloride. |
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Answer» Solution :GIVEN : `DeltaH_f (NaCl)=30.4 kJ =30400 "J MOL"^(-1)` `DeltaS_f (NaCl)=28.4 JK^(-1) mol^(-1)` `T_f`=? `DeltaS_f =(DeltaH_f)/(DeltaT_f)` `T_f =(DeltaH_f)/(DeltaS_f)` `T_f=(30400 "J mol"^(-1))/(28.4 J K^(-1) "mol"^(-1))` `T_f` =1070.4 K |
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