30 cc of (M)/(3) HCl , 20 cc of (M)/(2) HNO_(3) and40 cc of (M)/(4) NaOH solutions are mixed and the resulting solution is

30 cc of (M)/(3) HCl , 20 cc of (M)/(2) HNO_(3) and40 cc of (M)/(4) Na

1.	30 cc of (M)/(3) HCl , 20 cc of (M)/(2) HNO_(3) and40 cc of (M)/(4) NaOH solutions are mixed and the resulting solution is
Answer» 2 1 3 8 Solution :Total millimolar of `H^(+)=(30xx(1)/(3))+(20xx(1)/(2))` `=10+10=20` Total MILLIMOLES of `OH^(-)=40xx(1)/(4)=10` `:. H^(+)` IONS left after neutralization = 10 MILLIMOLE Volume of solution `=1 dm^(3) = 1000cc` Hence, molarityof `H^(+)` ions `=(10)/(1000)M= 10^(-2)M` `:. PH =- log [H^(+)]=-log 10^(-2)=2`