30 mL of mixture of methane and ethane in x:y ratio by volumes on combustion gave 40 mL of carbon dioxide. If 30 mL of mixture is taken in y: x ratio, what is the volume of carbondioxide obtained under similar conditions?

30 mL of mixture of methane and ethane in x:y ratio by volumes on comb

1.	30 mL of mixture of methane and ethane in x:y ratio by volumes on combustion gave 40 mL of carbon dioxide. If 30 mL of mixture is taken in y: x ratio, what is the volume of carbondioxide obtained under similar conditions?
Answer» Solution :The combustion of methane and ethane is given by the equations `CH_(4)overset(O_(2))rarrCO_(2)+2H_(2)O, C_(2)H_(6)overset(O_(2))rarr 2CO_(2)+3H_(2)O` 1 volume of `CH_(4) = 1` volume of `CO_(2)` 1 volume of `C_(2)H_(6) = 2` volume of `CO_(2)` Let, volume of `CH_(4)` in the given mixture `= X` Let, volume of `C_(2)H_(6)` in the given mixture `= y` Then, `x + y = 30""x + 2Y = 40` `y = 10""x = 30 - 10 = 20` If y mL of `CH_(4)` is taken, the volume of `CO_(2)` obtained = y = 10 mL If x mL of `C_(2)H_(6)` is taken, the volume of `CO_(2)` obtained `= 2x = 2 xx 20 = 40 mL` The volume of carbondioxide obtained by the combustion of 30 mL of `y: x` volumes of methane and ethane `= 10 + 40 = 50 mL`