30 mL of mixture of methane and ethane in x:y ratio by volumes on combustion gave 40 mL of carbon dioxide. If 30 mL of mixture is taken in y: x ratio, what is the volume of carbondioxide obtained under similar conditions?

30 mL of mixture of methane and ethane in x:y ratio by volumes on comb

1.	30 mL of mixture of methane and ethane in x:y ratio by volumes on combustion gave 40 mL of carbon dioxide. If 30 mL of mixture is taken in y: x ratio, what is the volume of carbondioxide obtained under similar conditions?
Answer» <html><body><p></p>Solution :The combustion of methane and ethane is given by the equations <br/> `CH_(4)overset(O_(2))rarrCO_(2)+2H_(2)O, C_(2)H_(6)overset(O_(2))rarr 2CO_(2)+3H_(2)O` <br/> 1 volume of `CH_(4) = 1` volume of `CO_(2)` <br/> 1 volume of `C_(2)H_(6) = 2` volume of `CO_(2)` <br/> Let, volume of `CH_(4)` in the given mixture `= <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>` <br/> Let, volume of `C_(2)H_(6)` in the given mixture `= y` <br/> Then, `x + y = 30""x + <a href="https://interviewquestions.tuteehub.com/tag/2y-301307" style="font-weight:bold;" target="_blank" title="Click to know more about 2Y">2Y</a> = 40` <br/> `y = 10""x = 30 - 10 = 20` <br/> If y mL of `CH_(4)` is taken, <br/> the volume of `CO_(2)` obtained = y = 10 mL <br/> If x mL of `C_(2)H_(6)` is taken, <br/> the volume of `CO_(2)` obtained `= 2x = 2 xx 20 = 40 mL` <br/> The volume of carbondioxide obtained by the combustion of 30 mL of `y: x` volumes of methane and ethane `= 10 + 40 = 50 mL`</body></html>