300 K temperature at 2.0xx10^(4) Pa pressure volume of 0.09 mole CO_(2) gas is 112.0xx10^(-3)m^(3)then calculate volume at 4.0xx10^(4) Pa ?

300 K temperature at 2.0xx10^(4) Pa pressure volume of 0.09 mole CO_(2

1.	300 K temperature at 2.0xx10^(4) Pa pressure volume of 0.09 mole CO_(2) gas is 112.0xx10^(-3)m^(3)then calculate volume at 4.0xx10^(4) Pa ?
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`64.2xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m^(3)`<br/>`p_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)V_(1)=p_(2)V_(2)`<br/>`therefore V_(2)=(p_(1)V_(1))/(p_(2))=(2.0xx10^(4)Pa xx112.0xx10^(-3)m^(3))/(4.0xx10^(4)Pa)`<br/>`= 64.2xx10^(-3)m^(3)`<br/>(Note : As the pressure divided the volume become half.)</body></html>