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32 mg of pure `._(94)^(238)PuO_(2)` has an activity of `6.4 xx 10^(7) sec^(-1)` (i) What will be the half life of `._(94)^(238)Pu` in years? (ii) What amount of `PuO_(2)` will remain if 100 mg `PuO_(2)` is kept for 500 years? |
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Answer» (i) Mass of `.^(238)Pu = (238)/(270) xx 32 = 28.207 mg` Rate `= (0.693)/(t_(1//)) xx (w)/("At.wt") xx N` `6.4 xx 10^(7) = (0.693)/(t_(1//2)) xx (28.207 xx 10^(-3))/(238) xx 6.023 xx 10^(23)` `t_(1//2) = 7.729 xx 10^(11) sec = 2.45 xx 10^(4)` years (ii), `(0.693)/(t_(1//2)) = (2.303)/(t) log_(10) ((N_(0))/(N))` `(0.693)/(2.45 xx 10^(4)) = (2.303)/(5000) log_(10) ((100)/(N))` `N = 86.7` mg |
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