34 . 05 mL of phosphorus vapours weigh 0.0625 g at 546 .^(@)C and 0.1 bar pressure . What is the molart mass of phosphorus ?

34 . 05 mL of phosphorus vapours weigh 0.0625 g at 546 .^(@)C and 0.1

1.	34 . 05 mL of phosphorus vapours weigh 0.0625 g at 546 .^(@)C and 0.1 bar pressure . What is the molart mass of phosphorus ?
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to gas <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>, <br/> `PV = nRT` <br/>or `PV =w/M RT` <br/> Given : `P = 0.1 " bar," V =340.5 mL = 340.5 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) dm^3, W = 0.0625 g, R = 0.0831 " bar " dm^3 K^(-1) mol^(-1)` <br/> `T = 546^@C = 819 K, M` = ? <br/> `:. M=(W.R.T)/(P.V)= (0.0625 xx0.0831 xx 819)/(0.1 xx 340.5 xx 10^(-3))` <br/> = `124.92 g mol^(-1)` <br/>Hence, molar <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of phosphorus is `124.92 g mol^(-1)`.</body></html>