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34.95 ml of phosphorus vapour weighs 0.0625gat 0.1 bar pressure. What is the molar mass of phosphorus ? |
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Answer» Solution :`PV=nRT` `0.1"bar" xx(34.*05)/(10000L)=(0*0625)/(M) xx0*083xx819K` `M=(0*0625xx0*083xx819Kxx1000)/(34*05xx0*1)=(4248*5625)/(3*405)=1247*7 "MOL"^(-1)` |
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