1.

3C_(2)H_(2) hArr C_(6) H_(6) the above reaction is performed in a I lit vessel. Equilibrium is established when 0.5 mole of benzene is present at certain tempe-rature. If equilibrium constant is 4 lit^(2) "mole"^(-2) The total number ot moles of the substances present at cquilibrium,

Answer»

0.5
1
1.5
2

Solution :`3C_(2)H_(2(g)) HARR C_(6)H_(6(g))`
`K_(C)=([C_(6)H_(6)])/([C_(2)H_(2)]^(3)), 4=(0.5)/([C_(2)H_(2)]^(3)) implies [C_(2)H_(2)]^(3)=(1)/(8)`
`[C_(2)H_(5)]=0.5=(n)/(v) implies n=0.5`
Total no. of moles of `C_(2)H_(2)` & `C_(6)H_(6)` at equilibrium = 0.5+0.5=1


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