3O_(2) harr 2O_(3). Oxygen is ozonised until the partial pressures of both gases become equal at equilibrium. Which statements are correct if P_(eq) = 10 atm ?

3O_(2) harr 2O_(3). Oxygen is ozonised until the partial pressures of

1.	3O_(2) harr 2O_(3). Oxygen is ozonised until the partial pressures of both gases become equal at equilibrium. Which statements are correct if P_(eq) = 10 atm ?
Answer» 60% oxygen is ozonised by volume mol. wt at equilibrium = 40 `K_(P)` = 0.2 atm `K_(P)`= 0.5 atm Solution : PARTIAL PRESSURES are EQUAL `implies 1-ALPHA=(2alpha)/(3) implies alpha=(3)/(5)=60%` `(D)/(d)=1+(n-1)alpha=1+((-1)/(3))alpha` `(32)/(d)=(4)/(5), d=40` `2P=P_(eqm) implies P=(10)/(2)=5` `:. K_(P)=(P^(2))/(P^(3))=(1)/(P)=0.2 atm^(-1)`