4.0 g of argon (at mass = 40) in a bulb at a temperature of TK had a pressure P atm. When the bulb was placed in hotter bath at a temperature 50^(@) more than the first one, 0.8 g of gas had to be removed to get the original pressure. T is equal is

4.0 g of argon (at mass = 40) in a bulb at a temperature of TK had a p

1.	4.0 g of argon (at mass = 40) in a bulb at a temperature of TK had a pressure P atm. When the bulb was placed in hotter bath at a temperature 50^(@) more than the first one, 0.8 g of gas had to be removed to get the original pressure. T is equal is
Answer» 510 K 200 K 100 K 73 K Solution :According to ideal gas eqatio `PV = w (RT)/(M) " or " WT = (PV)/(R) .M` or `w_(1)T_(1) = w_(2) T_(2)` when P and V are constant Hence `4 xx T = 3.2 (T + 50)` or `T = 200 K`