4.0 g of argon (at mass = 40) in a bulb at a temperature of TK had a pressure P atm. When the bulb was placed in hotter bath at a temperature 50^(@) more than the first one, 0.8 g of gas had to be removed to get the original pressure. T is equal is

4.0 g of argon (at mass = 40) in a bulb at a temperature of TK had a p

1.	4.0 g of argon (at mass = 40) in a bulb at a temperature of TK had a pressure P atm. When the bulb was placed in hotter bath at a temperature 50^(@) more than the first one, 0.8 g of gas had to be removed to get the original pressure. T is equal is
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/510-324427" style="font-weight:bold;" target="_blank" title="Click to know more about 510">510</a> K<br/>200 K<br/>100 K<br/>73 K</p>Solution :According to ideal gas eqatio <br/> `<a href="https://interviewquestions.tuteehub.com/tag/pv-593601" style="font-weight:bold;" target="_blank" title="Click to know more about PV">PV</a> = w (RT)/(M) " or " <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a> = (PV)/(R) .M` <br/> or `w_(1)T_(1) = w_(2) T_(2)` when P and V are constant <br/> Hence `4 xx T = 3.2 (T + <a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>)` <br/> or `T = 200 K`</body></html>