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4.215 g of a metallic carbonate was heated in a hard glass tube and the CO_2 evolved was found to measure 1336 mL at 27°C and 700 mm pressure. What is the equivalent weight of the metal? |
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Answer» Solution :Volume of `CO_2` at NTP `= ( 1336 xx 273)/(300) xx (700)/( 760)` `= 1120` mL. Suppose the equivalent weight of the metal is E. `THEREFORE` equivalent weight of the metal carbonate `= (E + 30)` `(because "eq. wt. of"CO_(3)^(2-) = ( 60)/( 2) = 30)`. Now, equivalent of metallic carbonate = equivalent of `CO_2` `(4.215)/( E+30) = ( 1120("VOL. at NTP") )/( 11200 ("vol. of 1 eq. at NTP") )` `therefore E=12.15`. |
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