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4.215 g of a metallic carbonate was heated in a hard glass tube and the CO_2 evolved was found to measure 1336 mL at 27°C and 700 mm pressure. What is the equivalent weight of the metal?

Answer» <html><body><p></p>Solution :Volume of `CO_2` at NTP `= ( 1336 xx 273)/(300) xx (700)/( 760)` <br/> `= <a href="https://interviewquestions.tuteehub.com/tag/tildephi-fltildephi-ck-1120-268501" style="font-weight:bold;" target="_blank" title="Click to know more about 1120">1120</a>` mL. <br/> Suppose the equivalent weight of the metal is E. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` equivalent weight of the metal carbonate `= (E + 30)` <br/> `(because "eq. wt. of"CO_(3)^(2-) = ( 60)/( 2) = 30)`. <br/> Now, equivalent of metallic carbonate = equivalent of `CO_2` <br/> `(4.215)/( E+30) = ( 1120("<a href="https://interviewquestions.tuteehub.com/tag/vol-723961" style="font-weight:bold;" target="_blank" title="Click to know more about VOL">VOL</a>. at NTP") )/( 11200 ("vol. of 1 eq. at NTP") )` <br/> `therefore E=12.15`.</body></html>


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