1.

4.28g of NaOH is dissolved in water and the solution is made to 250 cc. what will be the molarity of the solution ?

Answer»

0.615 mol `L^(-1)`
0.428 mol `L^(-1)`
0.99 mol `L^(-1)`
0.301 mol `L^(-1)`

Solution :No. moles of `NAOH =(4.28)/(40)=0.107` ltbr. VOLUMEOF solution `=250cm^3`
`M=n/(V("in L"))=(0.107)/(250)xx1000=0.428mol L^(-1)`


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