4.4 g of an unknown gas occupies 2.24 L of volume under N.T.P. conditions. The gas may be :

4.4 g of an unknown gas occupies 2.24 L of volume under N.T.P. conditi

1.	4.4 g of an unknown gas occupies 2.24 L of volume under N.T.P. conditions. The gas may be :
Answer» `CO_(2)` CO `O_(2)` `SO_(2)` Solution :2.24 L of gas CORRESPOND to MASS = 4.4 g 22.4 L of gas correspond to mass `= (4.4)/(2.24) xx22.4` `= 44.0 g` The gas is `CO_(2)`.