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4.4 g of an unknown gas occupies 2.24 L of volume under N.T.P. conditions. The gas may be :

Answer» <html><body><p>`CO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>CO<br/>`O_(2)`<br/>`SO_(2)`</p>Solution :2.24 L of gas <a href="https://interviewquestions.tuteehub.com/tag/correspond-935558" style="font-weight:bold;" target="_blank" title="Click to know more about CORRESPOND">CORRESPOND</a> to <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> = 4.4 g <br/> 22.4 L of gas correspond to mass `= (4.4)/(2.24) xx22.4` <br/> `= 44.0 g` <br/> The gas is `CO_(2)`.</body></html>


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