4.4 g of an unknown gas occupies 2.24 L of volume under STP conditions

1.	4.4 g of an unknown gas occupies 2.24 L of volume under STP conditions. The gas may be ………………(A) CO2(B) CO (C) O2 (D) SO2
Answer» (A) \(CO_2\) Let say, the molar mass of unknown gas is M Then, Number of mole of unknown gas = \(\frac{4.4\,g}{M}\) As we know, 1 mole of any gas at STP occupy = 22.4 L of volume. \(\therefore\) Number of moles unknown gas = \(\frac{2.24}{22.4}=0.1\) mol Therefore, \(\frac{4.4}{M}=0.1\) \(M=\frac{4.4}{0.1}\) M = 44 g/mol In the given options only \(CO_2\) has molar mass of 44 g/mol Hence, the unknown gas will be \(CO_2\). Option : (A) CO₂

4.4 g of an unknown gas occupies 2.24 L of volume under STP conditions. The gas may be ………………(A) CO2(B) CO (C) O2 (D) SO2

Answer»

(A) \(CO_2\)

Let say, the molar mass of unknown gas is M

Then, Number of mole of unknown gas = \(\frac{4.4\,g}{M}\)

As we know,

1 mole of any gas at STP occupy = 22.4 L of volume.

\(\therefore\) Number of moles unknown gas = \(\frac{2.24}{22.4}=0.1\) mol

Therefore,

\(\frac{4.4}{M}=0.1\)

\(M=\frac{4.4}{0.1}\)

M = 44 g/mol

In the given options only \(CO_2\) has molar mass of 44 g/mol

Hence, the unknown gas will be \(CO_2\).

Option : (A) CO₂